10t^2-20t=45

Solution for 10t^2-20t=45 equation:

10t^2-20t=45

We move all terms to the left:

10t^2-20t-(45)=0

a = 10; b = -20; c = -45;
Δ = b2-4ac
Δ = -202-4·10·(-45)
Δ = 2200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2200}=\sqrt{100*22}=\sqrt{100}*\sqrt{22}=10\sqrt{22}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-10\sqrt{22}}{2*10}=\frac{20-10\sqrt{22}}{20}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+10\sqrt{22}}{2*10}=\frac{20+10\sqrt{22}}{20}
$